如何在不使用删除运算符的情况下删除由新创建的内存 [英] How Can I Delete Memory Created By New Without Using Delete Operator

问题描述

int * ptr;

ptr = new int a [20];



删除在不使用delete的情况下创建为20个整数的内存

int *ptr;
ptr=new int a[20];

delete memory created to 20 integers without using delete

推荐答案

语言C ++有一些规则，例如分配new的内存必须在释放时释放。



您可以：



1.覆盖命令new并使用您自己的实现删除

2.使用其他方法像malloc和free一样的内存管理。

3.在范围内分配内存。

4.使用一些auto_ptr。 （高级技术）





但永远不要骄傲：成为一个好公民，如果你想开发软件，你应该遵守规则。

the language C++ has some rules, for instance that memory which is allocated the new has to be freed with release.

You can:

1. overwrite the command new and delete with your own implementation
2. use other methods for memory managment like malloc and free.
3. allocate memory in scopes.
4. use some auto_ptr. (advanced technology)


But never ever ferget: be a good citizen and if you want to develop software you should stick to the rules.

你可以使用多种方法如果没有在程序中直接编写删除操作符，请执行此操作：

You could use a number of ways to to do it without literally writing the delete operator in your program:

#include <memory>
int main()
{
    int *ptr=new int[20];
    std::allocator<int>().deallocate(ptr, 20);
}

#include <memory>
int main()
{
    int *ptr=new int[20];
    std::default_delete<int[]>()(ptr);
}

#include <memory>
int main()
{
    int *ptr=new int[20];
    std::unique_ptr<int[]> p(ptr);
}

#include <boost/smart_ptr.hpp>
int main()
{
    int *ptr=new int[20];
    boost::scoped_array<int> p(ptr);
}

等



所有这些都在某处在内部执行delete []，并将ptr的副本作为参数，这是实际释放该内存的参数。

etc.

All of these somewhere internally execute delete[] with a copy of your ptr as the argument which is what actually deallocates that memory.

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