如何在不使用malloc或new运算符的情况下分配内存空间？ [英] How to allocate memory space without using malloc or new operator?

问题描述

当我的朋友昨天接受采访时，他被问到一个问题：
实现一个不使用* alloc或new操作符分配内存空间的函数，函数应该返回一个指向该地址的指针。
他和我都不能找到答案。

When my friend had his interview yesterday, he was asked a question: Implement a function that allocates memory space without using the *alloc or new operator, and the function should return a pointer to the address. Neither he nor I can find the answer.

推荐答案

我认为这个问题更多的是一个谜题显示了编程经验。我的解决方案将分配一个全局字节数组，将被用来代替堆：

I think the question is more of a puzzle than a question that shows experience with programming. My solution would be allocating a global byte-array, that would be used instead of the heap:

char heap[MAX_ALLOWED_MEM];

/*
   The following function uses 'heap' as raw memory!
   void* like_malloc(size_t bytes);
   ...
*/

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