如何使用alpha数字生成1000万个唯一数字？ [英] how to generate 10 million unique numbers using alpha numerics?

问题描述

如何使用字母数字生成1000万个唯一数字？

hai需要一种方法来生成1000万个唯一数字使用.net











谢谢提前。

how to generate 10 million unique numbers using alpha numerics?
hai need a method to generate 10 million unique numbers using .net





Thanks advance.

推荐答案

使用GUID生成唯一的字母数字值。



32个字符。



OR



选择3个字符和4个数字，然后使用序列数值并增加数字值。

for first for first char {

for second for second char {

For for second for second char {

For循环for Numbers {

}

}

}

}



所有你需要做的就是将数据保存到永久数据库之后的存储就像生成1000条记录一样。

Use GUID to generate unique alpha numeric value.

32 chars.

OR

Choose 3 char and 4 numbers and go with serial numeric value and increase value of number.
For loop for first char {
For loop for second char {
For loop for second char {
For loop for Numbers {
}
}
}
}

All you need to do is just save data to permanent storage like database after a chunk of number generated like 1000 records.

输出'00000'作为第一个数字和 '5yc1r' 为10000000 ^th 号码

This outputs '00000' as first number and '5yc1r' as 10000000^th number

static void Main(string[] args)
{
  const int BASE=36;
  char[] base36 = {'0','1','2','3','4','5','6','7','8','9','a','b',
                   'c','d', 'e','f','g','h','i','j','k','l','m','n',
                   'o','p','q','r','s','t','u','v','w','x','y','z'};

  int[] idx = { 0, 0, 0, 0, 0  };
  for (int n = 0; n < 10000000; ++n)
  {
    string s = string.Empty + base36[idx[4]]+ base36[idx[3]] + base36[idx[2]] + base36[idx[1]] + base36[idx[0]];
    Console.WriteLine(s);
    ++idx[0];
    if (idx[0] == BASE)
    {
      idx[0] = 0;
      ++idx[1];
      if (idx[1] == BASE)
      {
        idx[1] = 0;
        ++idx[2];
        if (idx[2] == BASE)
        {
          idx[2] = 0;
          ++idx[3];
          if (idx[3] == BASE)
          {
            idx[3] = 0;
            ++idx[4];
          }
        }
      }
    }
  }
}

string[] TenMillionsId = new string[10000000];

for (int i = 0; i < 10000000; i++)
{
    Guid h = Guid.NewGuid();
    TenMillionsId[i] = h.ToString();
}

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