如何生成不以0开头且具有唯一数字的随机4位数字? [英] How to generate a random 4 digit number not starting with 0 and having unique digits?
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问题描述
这几乎可以正常工作,但是数字有时以0开头:
This works almost fine but the number starts with 0 sometimes:
import random
numbers = random.sample(range(10), 4)
print(''.join(map(str, numbers)))
我找到了很多示例,但是没有一个可以保证序列不会以0
开头.
I've found a lot of examples but none of them guarantee that the sequence won't start with 0
.
推荐答案
我们生成1-9范围内的第一个数字,然后从其余数字中提取下一个3:
We generate the first digit in the 1 - 9 range, then take the next 3 from the remaining digits:
import random
# We create a set of digits: {0, 1, .... 9}
digits = set(range(10))
# We generate a random integer, 1 <= first <= 9
first = random.randint(1, 9)
# We remove it from our set, then take a sample of
# 3 distinct elements from the remaining values
last_3 = random.sample(digits - {first}, 3)
print(str(first) + ''.join(map(str, last_3)))
生成的数字是等概率的,我们一步就可以得到一个有效的数字.
The generated numbers are equiprobable, and we get a valid number in one step.
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