我转换这个权利...... [英] Am I converting this right...

问题描述

大家好，



我将字符串转换为二进制数，功能为

Hi All,

I am converting a string to a binary number with the function

BinaryVersionSerialNumber = Convert.ToString(SerialNumber, 2);

这似乎给出了一个二进制数，我可以把它放在SerialNumber的形式上，这是一个Int32（我认为是一个32位整数）我得到了很多帮助的转换工作昨天来自CPallini，然而逆转野兽让我有点困惑，我正在假设X'=（X ^ Y），会让你做X =（X'^ Y），但它没有好像。我的逻辑错误还是转换为二进制文件？





格伦（我需要更多咖啡！）



谢谢你建议，见下面的评论。我现在遇到的问题是如果执行按位运算

This appears to give a binary number which I can put on the form the SerialNumber which is an Int32 (a 32 bit integer I think) I got the conversion to work with a lot of help yesterday from CPallini, However reversing the beast has got me a little confused, I was working on the assumption that X' = (X^Y), would allow you to do X = (X'^Y), but it doesn't seem to. Is my logic wrong or has the conversion to binary broken ?


Glenn (I need more coffee!)

Thanks for the advice, see comments below. The issue I have now is if performing the bitwise operation

Result = PassCode;
          MessageBox.Show(Result.ToString());

          Result = (Result & 0xFFF00000);
          MessageBox.Show(Result.ToString());

结果从给出0的字符串中清除，看来int32是结果

当它是'和'用六角填料给出0.我有点困惑吗？

格伦

Result is cleared from the string giving 0, it would appear that the int32 that is Result
when it is 'and' with the Hex filler gives 0. I am a little confused by this?
Glenn

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