获得缺席和存在 [英] Get No of absents and presence
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问题描述
大家好......
i希望得到各个员工的总和(缺席)和总和(在场),下表结构澄清了我的问题...
--------------------------------- ---------------
日期 | Emp_id | Absents 或 Presence
----------------------------- -------------------
1-1-2012 | 1 | P
2-1-2012 | 1 | P
3-1-2012 | 1 | A
4-1-2012 | 1 | P
1-1-2012 | 2 | P
2-1-2012 | 2 | A
3-1-2012 | 2 | A
4-1-2012 | 2 | P
1-1-2012 | 3 | P
2-1-2012 | 3 | P
3-1-2012 | 3 | P
4-1-2012 | 3 | P
________________________________________________
1)在此表中有一个人员出勤表
2)P =存在。 A =缺席
我希望所有员工的存在和缺席次数如下所示
-------------------------------------------- -
Emp_id |否。 .presence | .absents
--------------------------- ------------------
1 | 3 (总和 P)| 1 (Sum A)
2 | 2 | 2
3 | 4 | 0
------------------------------- --------------
我不知道是否有可能......
请分享您的想法...
解决方案
尝试:
< pre lang =SQL> SELECT Emp_id,
SUM( CASE WHEN AorP = ' P' 那么 1 ELSE 0 END ),
SUM( CASE WHEN AorP = ' A' 那么 1 ELSE 0 END )
FROM MyTable
GROUP BY Emp_Id
Hi all...
i want get sum(absents) and sum(presence) for the individual employees,the following table structure is clarify my question...
------------------------------------------------
Date | Emp_id | Absents OR Presence
------------------------------------------------
1-1-2012 | 1 | P
2-1-2012 | 1 | P
3-1-2012 | 1 | A
4-1-2012 | 1 | P
1-1-2012 | 2 | P
2-1-2012 | 2 | A
3-1-2012 | 2 | A
4-1-2012 | 2 | P
1-1-2012 | 3 | P
2-1-2012 | 3 | P
3-1-2012 | 3 | P
4-1-2012 | 3 | P
________________________________________________
1)In this table has a emp attendance table
2)P=presence. A=absents
I want the number of presence and absents the all employees like below
---------------------------------------------
Emp_id | No.of.presence | No.of.absents
---------------------------------------------
1 | 3(sum of P) | 1(Sum of A)
2 | 2 | 2
3 | 4 | 0
---------------------------------------------
I don't know it's possible or not...
please share your ideas...
解决方案
Try:
SELECT Emp_id, SUM(CASE WHEN AorP='P' THEN 1 ELSE 0 END), SUM(CASE WHEN AorP='A' THEN 1 ELSE 0 END) FROM MyTable GROUP BY Emp_Id
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