如何找到连续缺席的日子 [英] how to find continuous absent days
本文介绍了如何找到连续缺席的日子的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我在编写存储过程时遇到问题,这些存储过程找到了连续的缺席天
chektime列显示用户在场
表如
i have problem to write stored procedure that find the continuous absent days
chektime column shows the user is present
table are as
CREATE TABLE [dbo].[CHECKINOUT](
[USERID] [int] NOT NULL,
[CHECKTIME] [datetime] NOT NULL,
[CHECKTYPE] [nvarchar](1) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
[VERIFYCODE] [int] NULL,
[SENSORID] [nvarchar](5) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
[WorkCode] [int] NULL,
[sn] [nvarchar](20) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
CONSTRAINT [aaaaaCHECKINOUT_PK] PRIMARY KEY NONCLUSTERED
(
[USERID] ASC,
[CHECKTIME] ASC
)WITH (PAD_INDEX = OFF, IGNORE_DUP_KEY = OFF) ON [PRIMARY]
) ON [PRIMARY]
请帮助我
在此先感谢
plz help me
thanks in advance
推荐答案
您能发表到目前为止所尝试的内容吗?
没有人会为你做功课.
Can you post what you have tried so far?
Noone will do your homework for you.
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