类的串行化到XML [英] SERIALIZATION OF CLASS TO XML

问题描述

你好朋友



请帮我创建一个类，这样在序列化后我会得到一个xml的格式：

< pre lang =HTML> <？ xml version = 1.0 encoding = UTF-8 ？>
< 消息 命令 = 点存款 UnitID = 0000 版本 = 1.6 >
< 状态 > GOOD < /状态 >
< 金额 > 200 < / Amount >
< TimeDate > 09/02/2004 08:13:52 AM < / TimeDate >
< 错误 / >
< PlayerName > Doe John < / PlayerName >
< PatronCard > 1900069847 < / PatronCard >
< /消息 >

解决方案

以下是我测试该代码的代码示例。您只需添加所需的属性即可。

 使用 System.IO; 
 使用 System.Xml.Serialization; 
 
 命名空间 ConsoleApp2912 
 {
  class  Program 
 {
 静态  void  Main（ string  [] args）
 {
  var  data =  new 信息（）; 
 data.Command =  点存款; 
 data.Version =   1.6; 
 data.UnitId =   0000; 
 data.Status =   GOOD; 
 data.Amount =  200 ; 
 
 
  var  serializer =  new  XmlSerializer（ typeof （消息））; 
 
 使用（ var  strem =  new  FileStream（  d：\\data.xml，FileMode。 OpenOrCreate））
 {
 serializer.Serialize（strem，data）; 
} 
 
} 
} 
 
 [XmlRoot（ElementName =  消息）] 
  public   class 消息
 {
 [XmlAttribute（AttributeName =  命令）] 
  public   string 命令{ get ;  set ; } 
 
 [XmlAttribute（AttributeName =   UnitID）] 
  public   string  UnitId { get ;  set ; } 
 
 [XmlAttribute（AttributeName =   Version）] 
  public   string 版本{ get ;  set ; } 
 
 [XmlElement（ElementName =  状态）] 
  public   string 状态{ get ;  set ; } 
 
 [XmlElement（ElementName =  金额）] 
  public   long 金额{ get ;  set ; } 
} 
} 

如果您想要最容易同时使用的最全面的解决方案，请不要使用 XmlSeializer ，改为使用数据合约：

http://msdn.microsoft.com/en-us/library/ms733127.aspx [ ^ ]。



另请参阅我的我主张这种方法的过去答案：

创建属性文件。 .. [ ^ ]，

如何在表单应用程序中使用XML文件编写器和阅读器？ [ ^ ]。

-SA

Hello friends

Please help me to create a class so that after serialization i will get a xml of format this:

<?xml version="1.0" encoding="UTF-8" ?>
<Message Command="Point Deposit" UnitID="0000" Version="1.6">
  <Status>GOOD</Status>
  <Amount>200</Amount>
  <TimeDate>09/02/2004 08:13:52 AM</TimeDate>
  <Error />
  <PlayerName>Doe John</PlayerName>
  <PatronCard>1900069847</PatronCard>
</Message>

解决方案

the following is the code sample i tested that code. You just add your required property as you like

using System.IO;
using System.Xml.Serialization;

namespace ConsoleApp2912
{
    class Program
    {
        static void Main(string[] args)
        {
            var data = new Message();
            data.Command = "Point Deposit";
            data.Version = "1.6";
            data.UnitId = "0000";
            data.Status = "GOOD";
            data.Amount = 200;


            var serializer = new XmlSerializer(typeof (Message));

            using (var strem = new FileStream("d:\\data.xml", FileMode.OpenOrCreate))
            {
                serializer.Serialize(strem, data);
            }

        }
    }

    [XmlRoot(ElementName = "Message")]
    public class Message
    {
        [XmlAttribute(AttributeName = "Command")]
        public string Command { get; set; }

        [XmlAttribute(AttributeName = "UnitID")]
        public string UnitId { get; set; }

        [XmlAttribute(AttributeName = "Version")]
        public string Version { get; set; }

        [XmlElement(ElementName = "Status")]
        public string Status { get; set; }

        [XmlElement(ElementName = "Amount")]
        public long Amount { get; set; }
    }
}

If you want the most comprehensive solution which is the easiest to use at the same time, don't use XmlSeializer, use Data Contract instead:
http://msdn.microsoft.com/en-us/library/ms733127.aspx[^].

Please see also my past answers where I advocate this approach:
Creating property files...[^],
How can I utilize XML File streamwriter and reader in my form application?[^].

—SA

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