合并列表中的值 [英] Merging values in list

问题描述

我创建了一个列表如下：

I have created a list as below:

列表 < string>
templist = new
List < string>

string 。 添加 （ new
< span lang ="EN-IN"style ="background：rgb（239,240,241）; color：＃101094; font-family：Consolas; font-size：10pt"> string （）{ 名称 = "crank
arm" ， 
PartId = 1234 ，
地址 =
"" ，city =
"" }）;

string.Add(new string() {Name="crank arm",  PartId=1234, Address = " ",city = " "});

string 。 添加 （ new
< span lang ="EN-IN"style ="background：rgb（239,240,241）; color：＃101094; font-family：Consolas; font-size：10pt"> string （）{
Name = " crank
arm" ，
PartId =
"" ， 地址
= "纽约" ，city
= "" }）;

string.Add(new string() { Name="crank arm", PartId = " ",Address = "New York",city = " " });

字符串 。 添加 （ 新
string （）{
名称 = "crank arm" ，
PartId =
"" ，
地址 =
"" ，city =
" USA" }）;

string.Add(new string() { Name="crank arm", PartId = " ", Address = " ",city = "USA"});

我需要将所有三条记录合并为一条记录并存储在同一个列表中。

I need to merge all the three records into a single record and store it in the same list.

必需输出：

" crank arm"，"1234"，"New York"，"USA"

推荐答案

再次，

public class Record
{
    public string Name;
    public string PartId;
    public string Address;
    public string City;
}

var templist = new List<Record>
{    new Record { Name = "crank arm", PartId = "1234", Address = " ", City = " " },
     new Record { Name = "crank arm", PartId = " ", Address = "New York", City = " " },
     new Record { Name = "crank arm", PartId = " ", Address = " ", City = "USA" }
};

var mergedByName = from element in templist
                   group element by element.Name into g
                   select new Record
                   {
                        Name = g.Key,
                        PartId = g.Max(e => e.PartId),
                        Address = g.Max(e => e.Address),
                        City = g.Max(e => e.City)
                   };

templist.AddRange(mergedByName);

foreach (var record in templist)
    Console.WriteLine(

" {record.Name}，{record.PartId}，{record .Address}，{record.City}"）;

"{record.Name},{record.PartId},{record.Address},{record.City}");

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