根据列表中的条件合并列表项 [英] Merge list items based on condition within the list

问题描述

我有一个项目清单: 例如:

I have a list of items : eg:

a = ['IP 123 84', 'apple', 'mercury', 'IP 543 65', 'killer', 'parser', 'goat',
     'IP 549 54 pineapple', 'django', 'python']

我想根据条件合并列表项目，即合并所有项目，直到以IP开头的项目. 我想要的输出是:

I want to merge the list items based on condition i.e merge all the items till the item that starts with IP. The output I want is :

a = ['IP 123 84 apple mercury', 'IP 543 65 killer parser goat',
     'IP 549 54 pineapple django python']

请提出建议.

推荐答案

使用生成器.

def merge(x, key='IP'):
    tmp = []
    for i in x:
        if (i[0:len(key)] == key) and len(tmp):
            yield ' '.join(tmp)
            tmp = []
        tmp.append(i)
    if len(tmp):
        yield ' '.join(tmp)

a = ['IP 123 84','apple','mercury','IP 543 65','killer','parser','goat','IP 549 54 pineapple','django','python']
print list(merge(a))

['IP 123 84 apple mercury', 'IP 543 65 killer parser goat', 'IP 549 54 pineapple django python']

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