什么可能导致这个未解决的外部符号异常？ [英] What could be possibly causing this unresolved external symbol exception?

问题描述

所以，我正在编写自己的静态库，到目前为止它运行良好。我正在尝试用C ++实现Python。为了让自己更容易，我将调用Python放入他们自己的函数中，Py_Arg：

So, I''m writing my own static library, and so far it was working well. I''m trying to implement Python in C++. To make it easier on myself, I put the calls to Python into their own function, Py_Arg:

#include "exampleApp.h"

std::string test()
{
	char* paras[] = {"123", "345"};
	Py_Arg("test", "multiply", (char*)paras);
	return "";
}

int Py_Arg(char* fileName[], char* funcName[], char* argv[])
{
//And it runs the code required... it shouldn't be important in regards to my question...
}

在我的头文件exampleApp.h中......

And, in my header file "exampleApp.h"...

#include <string>
#include <string.h>
#include <iostream>
#include "Python/Includes/Python.h"

std::string test();
int Py_Arg(char*, char*, char*);

而且，在我的应用程序来测试库...

And, in my app to test the library...

#include "stdafx.h"
#include <exampleApp.h>

int main(int argc, char* argv[])
{
	test();
	std::system("PAUSE");
	return 0;
}

现在，在VS中，我已经将exampleApp.lib库导入了测试项目。如您所见，我还指定了标题位置。但是，当我尝试运行程序时...

Now, in VS I have imported the exampleApp.lib library the test project. I also, as you can see, specified the header location. However, when I try to run the program...

error LNK2001: unresolved external symbol "int __cdecl Py_Arg(char *,char *,char *)" (?Py_Arg@@YAHPAD00@Z)

当我从库中完全删除Py_Arg函数时，它执行正常。但由于某种原因，它无法看到Py_Arg函数。这是否与char *参数有关？我现在正在试验整个char *，char * []，const char []等等，我很迷茫。任何帮助将不胜感激。



提前谢谢。

When I remove the Py_Arg function completely from the library, it executes fine. But for some reason it can''t see the Py_Arg function. Does this have to do with the char* arguments it takes? I''m kind of experimenting with the whole char*, char*[], const char[], etc right now and I''m very lost. Any help would be greatly appreciated.

Thanks in advance.

推荐答案

我会说你的功能定义错了：

I''d say your function definition is wrong:

int Py_Arg(char* fileName[], char* funcName[], char* argv[])

尝试改为

try instead

int Py_Arg(char* fileName, char* funcName, char* argv)

这至少是链接器正在搜索的内容。

That''s at least what the linker is searching for.

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