简单的程序不倒数 [英] simple program not counting down

问题描述

我是c语言的新手，我决定写这个程序，谁能告诉我为什么它不从输入的数字递减到0?

hi im very new to c and i decided to write this program, can anyone tell me why its not counting down from the number entered to 0?

#include <stdio.h>

int printloop(int k )
{
    int b;
        for (b = k; b < 0; b--)
     printf("%d\n",b);
}

int main()
{
int c;

scanf("%d",&c);
if( c > '0' && c < '6')

printloop(c);

return 0;
}

推荐答案

以以下内容开始:

To start with:

if( c > '0' && c < '6')

>
c是定义的整数，但是您将其与字符"0"&进行比较. ``6''.删除0和amp;附近的引号6

c is an integer defined but you compare it with a character ''0'' & ''6''. Remove quotes around 0 & 6

因为在您的for (b = k; b < 0; b--)中，您不允许它执行任何工作.
第二子句"b< 0"表示仅当b< b等于0时，该循环才会运行. 0.
由于您将b == k设置为大于0，因此循环将不会运行.
您的解决方案是for (b = k; b >= 0; b--)

Because in your for (b = k; b < 0; b--), you aren''t allowing it to do any work.
The second clause "b<0" indicates that this loop will only run if b < 0.
Since you set b == k which is greater than 0, the loop will not run.
Your solution is for (b = k; b >= 0; b--)

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