整数的倒数 [英] Reverse digits of an integer

问题描述

如何反转数字?

示例1:x = 123，返回321示例2:x = -123，返回-321

Example1: x = 123, return 321 Example2: x = -123, return -321

这是我的答案:

public int reverse(int x) {
    int result = 0;
    while(x != 0){
        result = result * 10 + x % 10;
        x = x / 10;
    }
    return result;
}

但是当我输入1534236469时，它将输出1056389759，这是错误的.您如何看待我的课程?谢谢.

but when I input 1534236469 , it will output 1056389759 , this is wrong. what do you think about my program? thanks.

推荐答案

您还可以输入x> 0(尽管没关系)，然后还必须考虑负数，所以我对逻辑进行了如下更改(也请使用长久以避免溢出):

You can write x >0 (doesn't matter though )also after that you have to consider negative numbers , I made that change to your logic as follows (Also use long long to avoid overflow):

      long long reverse(long long x)
      {

           int sign = 1;
           long long ans=0;
           if(x < 0)
             sign = -1;
           x = abs(x);
           while(x > 0)
           {
               ans *= 10;
               ans += x%10;
               x /=10;
           }
           return ans*sign;
      }

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