一个MxN数组到M * NxM * N [英] A MxN array to M*NxM*N

问题描述

你好，我是编程方面的新手，我陷入了一个问题:我有一个大小为[M，N]的二维数组A，我需要制作另一个大小为[M * N，M的数组B * N]具有来自第一个数组的值和具有相同索引的元素(例如B [3,1]和B [1,3])具有相同的值.最快的可编程方法是什么(它必须尽可能快，因为它可以处理成千上万的数字)

Hello, i`m kinda newbie in programming and i`m stuck into a problem:i have a bidimensional array A of size [M,N] and i need to make another array B of size [M*N,M*N] with the values from the first array and the elements with same indices (for example B[3,1] and B[1,3] ) have the same values. What is the fastest programmable way to to this (it must be as faster as it can,because it will work with thousands of numbers)

推荐答案

逐元素克隆，请使用Array.Copy方法.请参阅:
http://msdn.microsoft.com/zh-我们/library/system.array.copy%28v=vs.100%29.aspx [

To accelerate things and avoid element-by-element cloning, use Array.Copy methods. Please see:
http://msdn.microsoft.com/en-us/library/system.array.copy%28v=vs.100%29.aspx[^].

—SA

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