URL出现修整问题 [英] Having Trim Issues With URL's
本文介绍了URL出现修整问题的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
这是我正在运行的代码.
This is the code I am running.
void PrintBrowserInfo(IWebBrowser2 *pBrowser) {
BSTR bstr;
pBrowser->get_LocationURL(&bstr);
wprintf(L" 1 URL: %s\n\n", bstr);
myfile <<"\n 1 URL: << bstr;
/////////////////////////////////
std::wstring wsURL;
wsURL = bstr;
size_t DSlashLoc = wsURL.find(L"//");
if (DSlashLoc != wsURL.npos)
{
wsURL.erase(wsURL.begin(), wsURL.begin() + DSlashLoc + 6);
}
DSlashLoc = wsURL.find(L"/");
if (DSlashLoc != wsURL.npos)
wsURL.erase(DSlashLoc);
wprintf(L"\n 2 URL: %s\n\n", wsURL.c_str());
myfile <<"\n 2 URL: << wsURL.c_str();
///////////////////////////////////
SysFreeString(bstr);
}
探针就是这个……在第二组wprint上.
如果网址是http://www.codeproject.com
我得到
codeproject.com很棒.
但是,如果网址是http://stackoverflow.com
我得到
tackoverflow.com不太好.
我该如何解决?
打个招呼.
The probem is this...on the second set of wprint.
if a url is http://www.codeproject.com
I get
codeproject.com which is great.
however if a url is http://stackoverflow.com
I get
tackoverflow.com which is not so great.
How can I fix this?
Thnak you.
推荐答案
问题是您将DSlashLoc + 6作为结束偏移量.这将始终删除起始协议和冒号,//
和接下来的4个字符.
The issue is that you have DSlashLoc + 6 as the end offset. This will always remove the starting protocol and colon, the//
and the next 4 characters.
//First remove the http, https, ftp, ...
size_t DSlashLoc = wsURL.find(L"://");
if (DSlashLoc != wsURL.npos)
{
wsURL.erase(wsURL.begin(), wsURL.begin() + DSlashLoc + 3);
}
//Now remove the www. if it exists, otherwise leave it alone
DSlashLoc = wsURL.find(L"www.");
if (DSlashLoc == 0)
{
wsURL.erase(wsURL.begin(), wsURL.begin() + 4);
}
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