编辑/更新xml内容 [英] edit/update an xml content

问题描述

大家好，我想问一下如何使用csharp编辑xml文件中的1个特定内容?假设我有一个具有此值的xml文件

Hi guys i would like to ask how will i edit 1 specific content in my xml file using csharp? assuming i have an xml file that has this value

<?xml version="1.0" standalone="yes"?>
<NewDataSet>
  <xs:schema id="NewDataSet" xmlns="" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata">
    <xs:element name="NewDataSet" msdata:IsDataSet="true" msdata:UseCurrentLocale="true">
      <xs:complexType>
        <xs:choice minOccurs="0" maxOccurs="unbounded">
          <xs:element name="Table">
            <xs:complexType>
              <xs:sequence>
                <xs:element name="CityId" type="xs:int" minOccurs="0" />
                <xs:element name="CountryId" type="xs:int" minOccurs="0" />
                <xs:element name="RegionId" type="xs:int" minOccurs="0" />
                <xs:element name="City" type="xs:string" minOccurs="0" />
                <xs:element name="Longitude" type="xs:float" minOccurs="0" />
                <xs:element name="Latitude" type="xs:float" minOccurs="0" />
                <xs:element name="TimeZone" type="xs:string" minOccurs="0" />
                <xs:element name="Code" type="xs:string" minOccurs="0" />
              </xs:sequence>
            </xs:complexType>
          </xs:element>
        </xs:choice>
      </xs:complexType>
    </xs:element>
  </xs:schema>
  <Table>
    <CityId>27239</CityId>
    <CountryId>254</CountryId>
    <RegionId>124</RegionId>
    <City>Gray Mountain</City>
    <Longitude>35.8756</Longitude>
    <Latitude>-111.412</Latitude>
    <TimeZone>-07:00</TimeZone>
    <Code>753</Code>
  </Table>
  <Table>
    <CityId>35786</CityId>
    <CountryId>254</CountryId>
    <RegionId>148</RegionId>
    <City>Rapelje</City>
    <Longitude>45.9932</Longitude>
    <Latitude>-109.288</Latitude>
    <TimeZone>-07:00</TimeZone>
    <Code>756</Code>
  </Table>
  <Table>
    <CityId>4354</CityId>
    <CountryId>122</CountryId>
    <RegionId>2329</RegionId>
    <City>Tamana</City>
    <Longitude>32.917</Longitude>
    <Latitude>130.567</Latitude>
    <TimeZone>+09:00</TimeZone>
    <Code />
  </Table>

现在在第二行的cityid

now on cityid

35786

上，我想将城市值从

Rapelje

编辑到NewCity，我将如何完成该操作?请帮助谢谢.

to NewCity how am i going to accomplish that? please help thanks

推荐答案

一旦您的XML文件很小，我将首先建议基于DOM的解决方案(请参见下面列表中的第一项)；也可以考虑其他解决方案.下面，我对其进行概述:

As soon as your XML file is quite small, I would first advise the solution based on DOM (see first item from the list below); other solutions can also be considered. Below, I overview them:

1. 使用System.Xml.XmlDocument类.它实现了DOM接口；如果文档太大，则这种方法最简单，也足够好.
   请参见 http://msdn.microsoft.com/en-us/library/system.xml.xmlwriter.aspx [ http://msdn.microsoft.com/en-us/library/system.xml.xmlreader.aspx [ http://msdn.microsoft.com/en-us/library/system.xml.xmldocument.aspx [http://msdn.microsoft.com/en-us/library/bb387063.aspx [

1. Use System.Xml.XmlDocument class. It implements DOM interface; this way is the easiest and good enough if the size if the document is not too big.
   See http://msdn.microsoft.com/en-us/library/system.xml.xmldocument.aspx[^].
2. Use the classes System.Xml.XmlTextWriter and System.Xml.XmlTextReader; this is the fastest way of reading, especially is you need to skip some data.
   See http://msdn.microsoft.com/en-us/library/system.xml.xmlwriter.aspx[^], http://msdn.microsoft.com/en-us/library/system.xml.xmlreader.aspx[^].
3. Use the class System.Xml.Linq.XDocument; this is the most adequate way similar to that of XmlDocument, supporting LINQ to XML Programming.
   See http://msdn.microsoft.com/en-us/library/system.xml.xmldocument.aspx[^], http://msdn.microsoft.com/en-us/library/bb387063.aspx[^].

—SA

—SA

我建​​议 HtmlAgilityPack

http://htmlagilitypack.codeplex.com/ [ ^ ]

太棒了！了解XPath之后，您可以对XML文件甚至ASPX或ASCX文件进行任何操作，而它们的格式会混淆Microsoft XMLDocument.但是HtmlAgilityPack可以容忍错误的XML文件.

I suggest HtmlAgilityPack

http://htmlagilitypack.codeplex.com/[^]

It is fantastic! With knowing XPath, do whatever you want with XML files or even ASPX or ASCX files which their format will confuse Microsoft XMLDocument. but HtmlAgilityPack can tolerate erroneous XML files.

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