如何建立正则表达式匹配的字符串不包含＆QUOT; AU = 1＆QUOT;？ [英] How can I build the regex to match a string NOT containing "au=1"?

问题描述

正如标题所说...：）

As the title says... :)

你能不能帮我建立一个正则表达式匹配不含有字符串AU = 1？

Could you help me to build a regex to match a strings NOT containing "au=1"?

我在玩负向前查找，没有运气，但我敢肯定，我应该使用该得到的东西。

I was playing with negative lookahead with no luck but I'm quite sure that I should get something using that.

谢谢！

推荐答案

我终于用这个正则表达式做了

I finally did it with this regexp

^(?!.*au=1).*$

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