将数字四舍五入到下一个百位 [英] Rounding a digit to the next hundred position

问题描述

嗨朋友

我有一个像235的数字.我想将此数字四舍五入为300.例如85672-90000

我该如何实现

我使用了Math.cieling(number/100.000d)* 1000
但如果编号为312，则仍为312，而不是400

请帮助

问候
Chinnu

HI friends

I have a number like 235. i want to round this number to 300. Like 85672 - 90000

how can i achieve this

I used Math.cieling(number/100.000d)*1000
but if a no is 312 it wil remain as 312 not 400

Pls help

Regards
Chinnu

推荐答案

我刚刚尝试了它(因为它对我来说很好，除了乘法是一个数量级:

I just tried it (because it looks fine to me, excepting the multiply is out by an order of magnitude:

int i = 312;
Console.WriteLine(Math.Ceiling(i / 100.0d) * 100);

我得到的结果是"400".
您在做什么不同的事情?

The result I got was "400".
What are you doing differently?

这里有一个简单的解决方案:

Here''s a simple solution:

int x = 235;
int remainder = x % 100;
if (remainder > 0) {
    x = x + (100 - remainder);
}

这篇关于将数字四舍五入到下一个百位的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！