需要将两个字符串与NULL字符连接 [英] Need to concatenate two strings with NULL characters

问题描述

我正在尝试开发数据库迁移实用程序.
我正在使用以下功能来创建DSN.

SQLConfigDataSource(NULL，ODBC_ADD_DSN，"SQL Server"，ss)

此功能的最后一个参数是连接字符串.它的数据类型为LPCSTR.
此函数期望使用NULL字符作为分隔符.

简而言之，它期望字符串采用以下格式.
"ExpTempSQL \ 0SERVER =(本地)\ 0Trusted_Connection =是\ 0 \ 0"

如果您发现它们之间有NULL字符(\ 0).由于这个原因，我无法动态创建此字符串，因为strcat函数无法将字符串与NULL字符连接在一起，它会跳过NULL之后的字符串(我认为这是正确的行为).

在这方面的各种帮助将不胜感激.

Hi,

I am trying to develop a database migration utility.
I am using following function to create DSN.

SQLConfigDataSource(NULL, ODBC_ADD_DSN,"SQL Server",ss)

Last parameter of this fucntion is a connection string. It is of data type LPCSTR.
This function expects NULL character as a seperator.

In short it expects the string in following format.
"ExpTempSQL\0SERVER=(local)\0Trusted_Connection=yes\0\0"

If you notice there are NULL characters (\0) in between. Due to this i am not able to create this string dynamically as strcat function cannot concatenate the string with NULL characters, It skips the string beyond NULL(which is i think the correct behavior).

Help of any sort in this regard will be highly appreciated.

推荐答案

我遇到了同样的问题.您可以执行以下操作.

这是用于MFC的.

I had the same problem. You can do something like this.

This is for MFC.

CString sAttributes;
	
//Form the attributes string
sAttributes += "DSN=";
sAttributes += YOUR DSN NAME;
sAttributes += ''\0'';
sAttributes += "Server=";
sAttributes += SERVER NAME;
sAttributes += ''\0'';

您可以对其他属性执行相同的操作.

You can do the same for extra attributes.

struct testfunctor
{
void operator()(char& c) { if(c == ''|'') c = ''\0''; }
};
std::for_each( str.begin(), str.end(), testfunctor() );

这应该可行.

This should work..

是否可以使用指向字符串的指针自己复制它，然后复制其中的每个字符，并在收到两个NULL字符时停止行?

Isn''t it possible to copy it yourself using a pointer to the string and then copy every character in it and to stop when you receive two NULL characters in a row?

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