在简单程序中帮助创建方法所需的帮助 [英] Help needed creating methods within a simple program

问题描述

我需要在简单程序中创建方法的帮助.

我基本上创建了一个成绩报告表，在其中输入5个成绩会返回平均分数.我也有一个组合框，您必须在其中选择一个专业.我使用了if语句来检索字母等级，并使用开关来确定进入专业所需的等级.

显示的基本格式为:

I need help creating a method within a simple program.

I basically created a grade report sheet where I input 5 grades it returns the average score. I also have a combobox in which you have to select a major. I used an if statement to retrieve the letter grade and use a switch to determine the grade you need to get into a major.

The basic format I was shown was:

public string DetermineLetterGrade
            (double courseAverage)

然后显然是字母的返回

and then obviously a return of lettergrade

private void btnCalculateGrade_Click_1(object sender, RoutedEventArgs e)
        {
            string studentName;
            int homework1;
            int homework2;
            int quiz1;
            int quiz2;
            int finalExam;
            string letterGrade = "Incomplete";
            string major = "unknown";
            double homeworkContribution;
            double quizContribution;
            double finalExamContribution;
            double courseAverage;

            const double homeworkWeight = 0.25;
            const double quizWeight = .35;
            const double finalExamWeight = .40;

           

            studentName = (tbStudentName.Text);
            homework1 = Convert.ToInt32(tbHomework1.Text);
            homework2 = Convert.ToInt32(tbHomework2.Text);
            quiz1 = Convert.ToInt32(tbQuiz1.Text);
            quiz2 = Convert.ToInt32(tbQuiz2.Text);
            finalExam = Convert.ToInt32(tbFinal.Text);
            major = Convert.ToString(cbDepartment.SelectionBoxItem);
            homeworkContribution = (homework1 + homework2) / 2 * homeworkWeight;
            quizContribution = (quiz1 + quiz2) / 2 * quizWeight;
            finalExamContribution = (finalExam) * finalExamWeight;
            courseAverage = homeworkContribution + quizContribution + finalExamContribution;


   


            if (courseAverage >= 90)
            {
                letterGrade = "A";
            }
            else if (courseAverage > 80)
            {
                letterGrade = "B";
            }
            else if (courseAverage > 70)
            {
                letterGrade = "C";
            }
            else if (courseAverage > 60)
            {
                letterGrade = "D";
            }
            else
            {
                letterGrade = "F";
            }




    string businessCollegeRequirement = "unknown";
            switch (major)
            {
                case "Accounting":
                case "MIS":
                    businessCollegeRequirement = "need at least an B";
                    break;
                case "Economics":
                case "Finance":
                case "Marketing":
                    businessCollegeRequirement = "Need at least a C";
                    break;
                case "Management":
                    businessCollegeRequirement = "Need at least a D";
                    break;

            }

            lblResult.Content = studentName + "'s" + "Course Average:" + courseAverage;
            lblResult.Content += "\nletterGrade:" + letterGrade;
            lblResult.Content += "\nRequirement: " + businessCollegeRequirement;
            lblResult.Content += "\nMajor: " + major;


        }
    }//end class
}//end namespace

if (courseAverage >= 90)
           {
               letterGrade = "A";
           }
           else if (courseAverage > 80)
           {
               letterGrade = "B";
           }
           else if (courseAverage > 70)
           {
               letterGrade = "C";
           }
           else if (courseAverage > 60)
           {
               letterGrade = "D";
           }
           else
           {
               letterGrade = "F";
           }

推荐答案

到目前为止，我不喜欢任何答案，一点也不喜欢.数据应与代码分开；代码不应包含任何立即数(硬编码).应该是这样的:

I don''t like any of the Answers so far, not at all. Data should be separated from the code; code should not contain any immediate constants (hard-coded). It should be something like that:

//data associated with symbols:
enum Grade { F = -1, D = 60, C = 70, B = 80, A = 90, }

//...

//code, no numeric literals:
static Grade GetGrade(double age) {
    for (Grade grade = Grade.A; grade > Grade.F; grade--)
        if (age > (int)grade)
            return grade;
    return Grade.F;
} //GetGrade

—SA

—SA

然后，您的问题是什么，您可以轻松获得评分，让您的问题变得很清楚..

Then what is your problem , you can get the grade easily, make your problem clear..

<pre lang="cs">private String GetGrade(int courseAverage)<br />
        {<br />
            string letterGrade = "";<br />
            if (courseAverage >= 90)<br />
                letterGrade = "A";<br />
            else if (courseAverage > 80)<br />
                letterGrade = "B";<br />
            else if (courseAverage > 70)<br />
                letterGrade = "C";<br />
            else if (courseAverage > 60)<br />
                letterGrade = "D";<br />
            else<br />
                letterGrade = "F";<br />
            return letterGrade;<br />
        }</pre><br />

const double homeworkWeight = 0.25;
        const double quizWeight = .35;
        const double finalExamWeight = .40;

        private String CalculateGrade(string studentName, int homework1, int homework2, int quiz1, int quiz2, int finalExam)
        {
            string letterGrade = "Incomplete";

            double homeworkContribution = 0;
            double quizContribution = 0;
            double finalExamContribution = 0;

            homeworkContribution = (homework1 + homework2) / 2 * homeworkWeight;
            quizContribution = (quiz1 + quiz2) / 2 * quizWeight;
            finalExamContribution = (finalExam) * finalExamWeight;
            double courseAverage = homeworkContribution + quizContribution + finalExamContribution;

            if (courseAverage >= 90)
                letterGrade = "A";
            else if (courseAverage > 80)
                letterGrade = "B";
            else if (courseAverage > 70)
                letterGrade = "C";
            else if (courseAverage > 60)
                letterGrade = "D";
            else
                letterGrade = "F";

            return studentName + "'s" + "\nCourse Average : " + courseAverage + "\nletterGrade : " + letterGrade;

        }

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