我们在C ++中是否有等效的对象实现！！！ [英] Does we have equivalent Object implementation in c++!!!

问题描述

大家好，

我在Java Map< string，object>中有一个实现.
对象:类对象是类层次结构的根.每个类都有Object作为超类.所有对象(包括数组)都实现此类的方法.

我们在C ++中是否具有相同的实现方式，或者有人可以帮助我实现这一目标吗?


谢谢，
Mahesh

解决方案

不，您在C ++中没有这样的东西.但是，这很少需要.在大多数情况下，将完全不相关的对象存储在同一容器中没有任何意义.通常，所有类都继承自同一个基类，在这种情况下，您将基类用作所包含的类型.

您能详细解释一下您的问题到底是什么吗? "http://www.faqs.org/docs/think_java/TIJ303.htm#Heading1129">单根的层次结构" [书).
但是，正如Eckel指出的那样，您可以构建自己的单根类层次结构.为void *或更佳的情况是shared_ptr< void>.但是，如果您将不以某种方式关联的对象存储在同一集合中，则可能意味着您在某个地方缺少虚函数，并且过于依赖反射(C ++并非真正为之构建的) .

干杯，

灰

Hi All,

I have a implementation in Java Map<string,object>.
Object: Class Object is the root of the class hierarchy. Every class has Object as a superclass. All objects, including arrays, implement the methods of this class.

Do we have same kind of implementation in C++ or anyone help me how to achieve this?


Thanks,
Mahesh

解决方案

No, you don''t have something like this in C++. However, this is very rarely needed. Most of the time, it doesn''t make any sense to store objects completely unrelated in the same container. Usually, all your classes inherit from a same base class, in which case you use the base class as type contained.

Could you explain a bit more in details what you problem is exaclty ?

C++, unlike Java has not a single-rooted hierarchy (see, for instance, "The singly rooted hierarchy"[^] in Eckel''s "Thinking in Java" book).
However, as Eckel points out, you may build your own single-rooted class hierarchy.

The nearest thing to a common base class for everything (or rather a reference to a common base class) is void * or better still a shared_ptr<void>. However if you''re storing objects that aren''t related in some way in the same collection it probably means you''re missing a virtual function somewhere and leaning too much on reflection (which C++ isn''t really built for).

Cheers,

Ash

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