获得的点的坐标了一圈 [英] Getting Coordinates of a Point in a circle

问题描述

所以我写这吸引了我一个圆的类。我明明知道半径和圆心坐标。比方说，我要画一个点与该中心等于半径（R * 0.5）的一半的距离，并以59度角。
我怎样才能在正确的x和y坐标绘制点？

I $ C $在Android的CD，但我觉得编程语言是不相关的这个问题，它只是一些数学。

我AP preciate你的帮助。

解决方案

  X = R * COS（A）+ X0;
Y = R * SIN（A）+ Y0;
 

其中，（X0，Y0）是您的圆心，r为半径，A是角度

所以：

  X =（R * .5）* COS（59）+ X0;
Y =（R * .5）*罪（59）+ Y0;
 

so I have written a class which draws me a Circle. I obviously know the radius and the center coordinates of the circle. Let's say I want to draw a Point with a distance to the center equal to the half of the radius (r*0.5) and with an angle of 59 degrees. How can I draw the Point at the correct x and y coordinates?

I coded this in Android, but I think the programming language isn't relevant for this problem, it's just something mathematical.

I appreciate your help.

解决方案

x = r * cos(A) + x0;
y = r * sin(A) + y0;

where (x0, y0) is the centre of your circle, r is the radius and A is the angle.

So:

x = (r * .5) * cos(59) + x0;
y = (r * .5) * sin(59) + y0;

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