将球弹起一圈(Python Turtle) [英] Bouncing ball in a circle (Python Turtle)

问题描述

我目前正在使用Turtle制作圆形台球程序.我的问题是，一旦球到达圆的侧面以使其反弹，我就无法弄清楚需要给Python哪个角度或位置.这是我程序中需要修复的部分:

I am currently working on a circular billiards program using Turtle. My problem is that I can't figure out what angle or position I need to give Python once the ball has reached the sides of the circle in order to make it bounce. Here is the part of my program that needs to be fixed:

while nbrebonds>=0:
        forward(1)
        if (distance(0,y)>rayon): #rayon means radius 
            print(distance(0,y))
            left(2*angleinitial)  #I put this angle as a test but it doesn't work
            forward(1)
            nbrebonds+=(-1)

推荐答案

根据我对这个问题的了解，您应该能够使用turtle的heading()和towards()方法计算出所需的内容:

From what I was able to understand about this issue, you should be able to calculate what you need using turtle's heading() and towards() methods:

from random import *
from turtle import *

radius = 100
nbrebonds = 10

# draw circle around (0, 0)
penup()
sety(-radius)
down()
circle(radius)

# move turtle to somewhat random position & heading inside circle
penup()
home()
setx(randrange(radius//4, radius//2))
sety(randrange(radius//4, radius//2))
setheading(randrange(0, 360))
pendown()

while nbrebonds >= 0:
    forward(1)

    if distance(0, 0) > radius:

        incoming = heading()
        normal = towards(0, 0)
        outgoing = 2 * normal - 180 - incoming

        setheading(outgoing)

        forward(1)

        nbrebonds -= 1

mainloop()

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