发送PHP json_encode数组到jQuery [英] Sending PHP json_encode array to jQuery

问题描述

好的，我想我需要帮助！我搜索了所有可以考虑的关键字，但仍然无法找出答案，请帮忙.更多的是一个php家伙，而我刚开始使用jQuery.

ok, i guess I need help ! I searched with every keyword I could think off, but I still cant figure out, please help. Am more of a php guy, and I've just started with jQuery.

基本上，我想做的是从click函数发送一个jQuery帖子.根据我的php函数返回的值，显示/隐藏2个div.我的php函数返回一个带有2个简单值的"json_encode"数组，例如:

Basically, what I am trying to do is to send a jQuery post from a click function. And based on whatever is returned by my php function, show/hide 2 divs. My php function returns a "json_encode" array with 2 simple values, like such :

//================== PHP代码========================== =========

//==================PHP code ==================================

$message_for_user = "blah blah";
$calculatedValue = 1230;
$responseVar = array(
                    'message'=>$message_for_user,
                    'calculatedValue'=>$calculatedValue
                    );
echo (json_encode($responseVar));

//================== PHP代码结束========================= ==========

//==================PHP code End ==================================

我的JavaScript代码应该接受php返回的值:

My javascript code is supposed to accept the values returned by php :

//================== Javascript代码========================== =========

//==================Javascript code ==================================

$("div.calculator_result").click(function()
{
    $.post('myCalculator.php' ,{qid:itemID},function(response)
    {
        $("div.calculation_value").show(500).html(response['calculatedValue']);
        $("div#message_for_user").show(500).html(response['message']);
    }
}

//================== Javascript代码结束========================= ==========

//==================Javascript code End ==================================

不幸的是，在我的项目的javascript端，div并没有更新为我的php函数返回的值....我在哪里错了?我希望我的问题很清楚，如果没有，请告诉我，我将提供所需的任何其他信息.

Unfortunately, on the javascript side of my project, the divs are not updated with the values returned by my php functions .... where am I wrong? I hope I was clear in my question, if not, do let me know, and I shall provide any extra info required.

另一件事是，在更早的时候，我只回显一个值，即计算值(echo $ calculatedValue)，并且一切正常，只有当我转移到json编码数组中的echo后，不工作

Another thing is that earlier, I was echo'ing only a single value, that is the calculated value (echo $calculatedValue), and everything worked fine, its only after I shifted to echo'in the json encode array that things dont work

推荐答案

var json = $.parseJSON(response); alert(json.message);

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