如何从 PHP 数组中`json_encode()` 键? [英] How do I `json_encode()` keys from PHP array?

问题描述

我有一个像这样打印的数组

I have an array which prints like this

Array ( [0] => 1691864 [1] => 7944458 [2] => 9274078 [3] => 1062072 [4] => 8625335 [5] => 8255371 [6] => 5476104 [7] => 6145446 [8] => 7525604 [9] => 5947143 )

如果我 json_encode($thearray) 我得到这样的东西

If I json_encode($thearray) I get something like this

[1691864,7944458,9274078,1062072,8625335,8255371,5476104,6145446,7525604,5947143]

为什么名称未编码(例如 0、1、2、3 等)?我该怎么做才能让它出现在 json 代码中?完整代码如下

Why the name is not encoded (e.g 0, 1 , 2 , 3 etc) ? and how should I do to make it appear in the json code? the full code is below

  $ie = 0;
  while($ie   10)
  {
    $genid = rand(1000000,9999999);
     $temp[$ie] = $genid ;
     $ie++;
     }
     print_r($temp);

    $temp_json = json_encode($temp);
    print_r($temp_json);

推荐答案

你可以强制json_encode 使用一个对象，尽管您通过设置 JSON_FORCE_OBJECT 选项传递一个带有数字键的数组:

You can force that json_encode uses an object although you’re passing an array with numeric keys by setting the JSON_FORCE_OBJECT option:

json_encode($thearray, JSON_FORCE_OBJECT)

那么返回的值将是一个带有数字键的 JSON 对象:

Then the returned value will be a JSON object with numeric keys:

{"0":1691864,"1":7944458,"2":9274078,"3":1062072,"4":8625335,"5":8255371,"6":5476104,"7":6145446,"8":7525604,"9":5947143}

但是只有在真正需要对象时才应该这样做.

But you should only do this if an object is really required.

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