如何json_encode php数组但没有引号的键 [英] How to json_encode php array but the keys without quotes

问题描述

我正在尝试绘制(使用Flot)带有一些数据的饼图

I'm trying to plot (with Flot) a pie chart with some data

var data = <?php echo json_encode($data)?>

我从中得到的结果是:

var data = [
{"label":"Crear Usuario", "data":"2"},
{"label":"Impresoras", "data":"1"},
{"label":"Problema Correo", "data":"1"},
{"label":"Requisicion Equipo", "data":"1"},
{"label":"Sitio Web", "data":"1"}
]

这里的问题是我需要没有引号的 label 和 data，我已经尝试过 json_encode($data, JSON_NUMERIC_CHECK);但只从数字中删除引号.

The problem here is that I need the label and data without the quotes, I already tried json_encode($data, JSON_NUMERIC_CHECK); but only removes the quotes from the numbers.

以下格式是我需要的:

var data = [
    {label:"Crear Usuario",data:2}, ...

推荐答案

首先，您必须在 php 中生成数组，以便数据的值是整数，而不是字符串:

First, you have to generate your array in php so the data's value are integers, not strings:

我从你的 json_encode() 模拟了你的数组，我猜它看起来像这样(或者应该):

I emulated your array from your json_encode(), I guess it looks like this (or it should):

$array =  array(
                array("label" => "Crear Usuario",   "data" => 2),
                array("label" => "Impresoras",      "data" => 1),
                array("label" => "Problema Correo", "data" => 1),
                array("label" => "Requisicion Equipo", "data" => 1),
                array("label" => "Sitio Web", "data" => 1)
            );

    $data = json_encode($array);

• 请注意，2 和 1 没有加引号，因此它们是整数，这一点很重要.

然后您在 Javascript 中缺少 JSON.parse() 来实际将该输出转换为 json 对象:

Then you are missin in Javascript the JSON.parse() to actually make that output into a json object:

<script>
    var data = '<?php echo $data; ?>';
    var json = JSON.parse(data);
    console.log(json);
    console.log(json[0]);
</script>

• 请注意 var data = ... 是单引号，因此您可以将来自 php 的回显作为字符串捕获

console.log() 为我输出这个:

The console.log()'s output this for me:

[Object, Object, Object, Object, Object] // First console.log(): one object with the 5 Objects. 
Object {label: "Crear Usuario", data: 2} // secons console log (json[0]) with the first object 

看起来像你需要的，对吗?

Looks like what you need, am I right?

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