org.json.JSONException:对没有商品价值 [英] org.json.JSONException: No value for item
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问题描述
我收到了没有找到{用户名:萨拉}值{用户名:约翰}
JSONException
当我尝试使用Android应用程序来查看从MySQL数据库中的数据。
I get a No value for {"username":"sara"}{"username":"john"}
JSONException
when I attempt to view data from MySql database using android app.
08-20 04:26:39.396: W/System.err(4732): org.json.JSONException: No value for {"username":"sara"}{"username":"john"}
08-20 04:26:39.497: W/System.err(4732): at org.json.JSONObject.get(JSONObject.java:354)
08-20 04:26:39.497: W/System.err(4732): at org.json.JSONObject.getJSONArray(JSONObject.java:544)
08-20 04:26:39.517: W/System.err(4732): at com.example.phpapp.ViewData$MyTask.doInBackground(ViewData.java:69)
08-20 04:26:39.577: W/System.err(4732): at com.example.phpapp.ViewData$MyTask.doInBackground(ViewData.java:1)
08-20 04:26:39.606: W/System.err(4732): at android.os.AsyncTask$2.call(AsyncTask.java:287)
08-20 04:26:39.606: W/System.err(4732): at java.util.concurrent.FutureTask.run(FutureTask.java:234)
08-20 04:26:39.631: W/System.err(4732): at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:230)
08-20 04:26:39.636: W/System.err(4732): at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1080)
08-20 04:26:39.636: W/System.err(4732): at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:573)
08-20 04:26:39.636: W/System.err(4732): at java.lang.Thread.run(Thread.java:856)
PHP code
$con = mysql_connect($dbhost, $dbuser, $dbpass) or die("can't connect");
$db = mysql_select_db($dbname) or die("no such db name");
$query = "select username from users";
$result = mysql_query($query);
while($row= mysql_fetch_array($result)){
echo json_encode($row);
}
jsonArray
{"username":"sara"}{"username":"john"}
的Android code
HttpResponse response = client.execute(post);
HttpEntity entity = response.getEntity();
InputStream is = entity.getContent();
BufferedReader br = new BufferedReader(new InputStreamReader(is));
String str = "";
while((str = br.readLine()) != null){
s.append(str+"\n");
mystr = s.toString();
}
JSONObject object = new JSONObject(mystr);
JSONArray Jarray = object.getJSONArray(mystr);
for (int i = 0; i < Jarray.length(); i++) {
JSONObject Jasonobject = Jarray.getJSONObject(i);
st = Jasonobject.getString("username");
alist.add(str);
}
如何解决此问题?谢谢
How to Solve this? Thanks
推荐答案
但问题是在这行
JSONArray Jarray = object.getJSONArray(mystr);
其中, myStr中= {用户名:萨拉} {用户名:约翰}
(从输入流中的数据)
所以在这里您试图访问一个JSON数组索引 myStr中
从JSONObject的对象
So here you are trying to access a JSON Array with index mystr
from JSONObject object
在技术上永远存在,因此它被赋予 JSONException:没有价值{用户名:萨拉} {用户名:约翰}
Which technically never exist so it is giving the JSONException: No value for {"username":"sara"}{"username":"john"}
解决方案
使用JJPA的答案,然后正确的PHP code
Correct PHP code using JJPA's Answer then
使用
JSONArray Jarray=new JSONArray(mystr);
这篇关于org.json.JSONException:对没有商品价值的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
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