错误org.json.JSONException:PROJECT_NAME没有值,这是我的json [英] error org.json.JSONException: No value for PROJECT_NAME This is my json

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问题描述

我收到错误org.json.JSONException:PROJECT_NAME没有值,这是我的json

I am getting the error org.json.JSONException: No value for PROJECT_NAME This is my json

{"PROJECTS":[ 
         {
            "PROJECT_NUMBER": "2062",
            "PROJECT_NAME": "OPW 51183"
         },
         {
            "PROJECT_NUMBER": "404",
            "PROJECT_NAME": "404"
         },
         {
            "PROJECT_NUMBER": "2125",
            "PROJECT_NAME": "OPW 50016"
         },
         {
            "PROJECT_NUMBER": ""
         },
         {
            "PROJECT_NUMBER": "2130",
            "PROJECT_NAME": "OPW 51151 63rd & Shirley SEW S"
         },
         {
            "PROJECT_NUMBER": "2159",
            "PROJECT_NAME": "OPW 51226"
         }
        ]

    }

和鳕鱼是:

for (int i = 0; i < innerProjectarray.length(); i++) 
    {

JSONObject obj=innerProjectarray.getJSONObject(i);
String projectnumber1=obj.getString("PROJECT_NUMBER");
String projectname1=obj.getString("PROJECT_NAME");
        }

如果密钥不存在,有什么方法可以找到密钥,那么np需要获取特定字符串的值.帮帮我,谢谢

Is there is any way to find the key if key not exist then np need to get the value od particular string Help me thanks

推荐答案

使用

Use has to check if key is present in Json. It returns true if this object has a mapping for name.

喜欢

for (int i = 0; i < innerProjectarray.length(); i++) {

    JSONObject obj = innerProjectarray.getJSONObject(i);
    if (obj.has("PROJECT_NUMBER")) {
        String projectnumber1 = obj.getString("PROJECT_NUMBER");
    }

    if (obj.has("PROJECT_NAME")) {
        String projectname1 = obj.getString("PROJECT_NAME");
    }
}


另一种方法是使用


Another way is to use optString which returns the value mapped by name if it exists, coercing it if necessary. Returns the empty string if no such mapping exists.

for (int i = 0; i < innerProjectarray.length(); i++) {

    JSONObject obj = innerProjectarray.getJSONObject(i);

    String projNum = obj.optString("PROJECT_NUMBER"); 
    String projName = obj.optString("PROJECT_NAME"); 
    // and use both values. 
}

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