Javascript拼接在jQuery .each()上中断了吗? [英] Javascript splice is breaking on jQuery .each()?

问题描述

var results = ['one', 'two', 'one hundred', 'three'];
var removal = [];
$.each(results, function(i) {
    removal.push(i);
    if (results[i].indexOf('one') == -1){
        console.log('Removing:' + results[i] + '(' + removal[i] + ')');
        results = results.splice(removal[i], 1);
    }
});

我有以下代码，但是删除第一个结果后，它就中断了.

I have the following code, but it is breaking after it removes the first result.

我希望它删除不包含"one"一词的所有内容.

I want it to remove anything that does not contain the word 'one'.

我想这很麻烦，因为一旦删除顺序，删除顺序就会更改.

I am guessing it is breaking because the removal order changes once one has been removed.

我在做什么错了?

推荐答案

在使用$.each()进行迭代时，不应拼接数组.

You shouldn't splice the Array while you're iterating it with $.each().

由于您要更改数组的长度，因此您将超出最终索引.

Since you're changing the length of the Array, you're going beyond the final index since.

只需使用for循环并在删除项目时调整i ...

Just use a for loop and adjust i when you remove an item...

var results = ['one', 'two', 'one hundred', 'three'];
var removal = [];
for(var i = 0; i < results.length; i++) {
    removal.push(i);
    if (results[i].indexOf('one') == -1){
        console.log('Removing:' + results[i] + '(' + removal[i] + ')');
        results.splice(i, 1);
        i--;
    }
};

请注意，我已对此进行了更改...

Note that I changed this...

results = results.splice(removal[i], 1);

对此...

results.splice(removal[i], 1);

您不希望这样做，因为splice()会修改原始文件并返回被删除的项目.

You don't want that since splice() modifies the original, and returns the item(s) removed.

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