洗牌Android中的数组 [英] Shuffling an Array in Android

问题描述

我很新的编程，我试图做一个程序，它需要一个数量从一个EditText然后生成和数组，然后洗牌，洗牌的数字出来敬酒。
这就是我的code模样。
我试图通过一些其他职位的洗牌阵列读，但我一直没能得到这个工作。

I am very new to Programming and am trying to make a program that takes a number from an EditText then generates and Array which is then shuffled and the shuffled numbers come out on toast. This is what my code looks like. I have tried reading through a number of other posts on shuffling arrays but I haven't been able to get this to work.

public class Home extends Activity  {

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.home);


        final EditText editText1 = (EditText) findViewById(R.id.editText1);  
        Button  goButton = (Button) findViewById(R.id.goButton);
        goButton.setOnClickListener(new View.OnClickListener() {

            @Override
            public void onClick(View arg0) {

                String no = editText1.getText().toString();
                int no2 = Integer.parseInt(no);

                int[] integerArray = new int[no2];
                for (int i = 0; i < no2; i++)  
                    integerArray[i] = i;

                Collections.shuffle(Arrays.asList(integerArray));
                {



                    Toast msg= Toast.makeText(getApplicationContext(),  integerArray[no2], Toast.LENGTH_LONG);

                    msg.show();
                }

            }
        });
    }
}

感谢您事先的任何帮助。
汤姆

Thank you in advance for any help. Tom

推荐答案

其实你不使用你的洗牌数组，但您创建的整型数组。
尝试，而不是：

Actually you don't use the array that you shuffled, but the integer array that you created. Try instead :

List<Integer> myArray = new ArrayList<Integer>(Arrays.asList(integerArray));
Collections.shuffle(myArray);

然后

Toast msg= Toast.makeText(getApplicationContext(),  myArray.get(no2-1), Toast.LENGTH_LONG);
msg.show();

另一种更好的方法是直接创建列表。

Another better approach would be to directly create the List.

 List<Integer> myArray = new ArrayList<Integer>(no2);
            for (int i = 0; i < no2; i++)  
                myArray.add(i);

        Collections.shuffle(myArray);

这篇关于洗牌Android中的数组的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！