C ++数组洗牌 [英] C++ Array Shuffle

问题描述

我是相当新的C ++和不明白的指针和引用函数参数。我有我想用费雪耶茨洗牌洗牌的数组。甲板被声明为

I'm fairly new to C++ and don't quite understand function parameters with pointers and references. I have an array of Cards that I want to shuffle using the Fisher-Yates shuffle. The deck is declared as

Card *deck[deckSize];

在这里deckSize已被宣布为24.数组初始化。
那么我所说的随机播放功能：

where deckSize has been declared as 24. The array is then initialized. I then call the shuffle function:

void shuffle (Card * deck[]) {
    int deckSize = 24;
    while (deckSize > 1) {
       long int k = lrand48();
       k = k %24;
       deckSize--;
       Card * temp = deck[deckSize];
       deck[deckSize] = deck[k];
       deck[k] = temp;
    }
}

如果我尝试调用的随机播放功能，我收到了赛格故障后打印卡的价值。如何做到这一点的指针是否正确？

If I try to print the value of a card after calling the shuffle function I get a seg fault. Any pointers on how to do this properly?

推荐答案

看起来，你的问题并不来自于code发布，它看起来在乍看之下不错，但是从它周围的code

It looks that your problem does not come from the code posted, which looks fine at a first glance, but from the code around it.

有关使用卡标准容器是什么？你必须填满它，先打印出来，看看它的确定，洗牌，然后重新打印。

What about using a standard container of cards ? You must fill it, print it first to see if it's ok, shuffle, and then print it again.

#include <vector>
std::vector<Card> deck; // Empty for now. Must be filled with cards.


void shuffle (std::vector<Card> & deck)
{
    int deckSize = 24;
    while (deckSize > 1) 
    {
       long int k = lrand48();
       k = k %24;
       deckSize--;
       Card temp = deck[deckSize];
       deck[deckSize] = deck[k];
       deck[k] = temp;
    }
}

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