使用ajax将变量传递到php文件不起作用 [英] passing a variable to php file using ajax not working

问题描述

我正在尝试使用ajax单击class("women")到一个php文件时传递一个变量，但是它不起作用.这是我的代码

I am trying to pass a variable when a class("women") is clicked using ajax to a php file but it is not working. Here is my code

jquery:

$('.women').click(function(){
    var test="hello";
    $.ajax({
    type: "POST",
    url: 'data.php',
    data: {'variable':test},
        success:function(data){
            console.log(data);
        },
    });
     $(".women").attr('href','data.php');
})

php代码:

if (isset($_POST['variable']))
{
    echo($_POST['variable']);
}
else
{
   echo ("failure");
}

html:

<li class="nav-item mr-auto ml-auto" data-target="#collapsewomen">
    <a class="nav-link active women productlink"  href="#">Women</a>
</li>

在控制台中，我可以看到"hello"，这意味着ajax在运行，但是一旦定向到php页面，我就会收到失败"的提示.我无法将测试变量传递给php文件

In the console I can see "hello" which mean ajax is working, but once directed to php page I get "failure". What I am not able to pass test variable to php file

推荐答案

ajax的目的是在不刷新页面的情况下将数据发送到URL.如果要重定向页面，则无需使用ajax.

The purpose of ajax is to send data to a URL without refreshing the page. If you want redirect the page, there is no use of using ajax.

进行ajax调用不会自动保存发送的数据，并且如果您重定向到该页面，则无法使用该数据.

Doing an ajax call will not automatically save the data sent and the data can't be use if you redirect to that page.

使用GET

$('.women').click(function(){
     var test="hello";
     window.location.href = "data.php?variable=" + test;
})

在您的PHP上

if (isset($_GET['variable']))
{
    echo($_GET['variable']);
}
else
{
   echo ("failure");
}

---

使用POST ，一种选择是使用隐藏形式，例如:

---

Using POST, one option is to use hidden form like:

在您的主页上:

$('.women').click(function(){
    var test = "hello";
    $('[name="variable"]').val(test);  //Update the value of hidden input
    $("#toPost").submit();             //Submit the form
})

HTML:

<a class="nav-link active women productlink"  href="#">Women</a>

<form id="toPost" action="data.php" method="POST">
  <input type="hidden" name="variable" value="">
</form>

在您的data.php上:

On your data.php:

<?php 
if (isset($_POST['variable']))
{
    echo($_POST['variable']);
}
else
{
   echo ("failure");
}

?>

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