通过ajax调用php文件不起作用 [英] call to php file via ajax not working

问题描述

这似乎是一个相对简单的问题，对于使用ajax来说我还很陌生，但是我看到了一篇有关触发OnClick事件时能够调用PHP脚本的文章.我试图破坏用户单击注销"链接后的会话，因此我想在发生OnClick事件时调用logout.php文件.我的问题是，单击链接后什么也没发生.

This seems like a relatively simple question, and I am pretty new to using ajax, but I saw a post about being able to call a PHP script when an OnClick event has been triggered. I am trying to destroy a session upon a user clicking the "Log Out" link, so I want to call the logout.php file when the OnClick event has occurred. My problem is that nothing happens when the link is clicked.

这是我的代码:

$(document).ready(function() {

// Expand Panel
$("#open").click(function(){        
    //when the user clicks the logout button
    $.ajax({
        url: "logout.php"
    )};
}); 
}); 



<div class="tab">
    <ul class="login">
        <li class="left">&nbsp;</li>
        <li><?php if(isset($_SESSION['username'])){echo $_SESSION['username'];}else{echo 'Hello Guest!';}?></li>
        <li class="sep">|</li>
        <li id="toggle">
            <a id="open" class="open" href="#">Log Out</a>      
        </li>
        <li class="right">&nbsp;</li>
    </ul> 
</div> <!-- / top -->

推荐答案

我想您希望显示logout.php文件的输出.我认为您的代码可能正在工作，但是您忘记了告诉ajax将接收到的数据放在何处.

I suppose that you expect the output of the logout.php file to show. I think that your code might be working but that you forgot to tell the ajax where to put the data that it receives.

尝试这样的事情:

$.ajax({
  url: 'logout.php',
  success: function(data) {
    $('.result').html(data);
    alert('Logout completed.');
  }
});

结果"指向您要将响应加载到的div.

Where "result" points to the div you want to load the response into.

这篇关于通过ajax调用php文件不起作用的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！