开始jQuery帮助 [英] Beginning jQuery help
问题描述
我正在尝试使用php和jQuery做一个简单的MySQL Admin.我从未使用过jQuery，因此我的代码可能相当值得一试.我的代码存在的问题是，当我单击按钮时，什么也没有发生.我知道甚至发生火灾，因为如果我在firefox中打开html文件(而不是使用file:///东西进入url)并单击它，它会在框中显示我的php代码，我希望将返回的内容放入其中.我想做的第一件事是连接到指定的数据库并返回表列表.这是我的代码
I'm trying to make a simple MySQL Admin thing with php and jQuery. I've never used jQuery so my code is probably quite lol-worthy. The problem I'm having with the code is that when I click the button, nothing happens. I know the even fires because if I open the html file in firefox (not going to the url, using the file:/// thing) and click it, it shows my php code in the box I want the returned content to go into. The first thing i'm trying to do is connect to the database specified and return a list of the tables. Heres my code
index.html
<html>
<head>
<script type='text/javascript' src='jquery.js'></script>
<script type='text/javascript'>
var Server = 'None';
var Username = 'None';
var Password = 'None';
var Database = 'None';
$("#connect").click(function() {
Server = $('#server').val();
Username = $('#username').val();
Password = $('#password').val();
Database = $('#database').val();
loadTables();
});
function loadTables() {
$.get("display.php", { server: Server, username: Username, password: Password, database: Database, content: "tables" },
function(data){
html = "<ul>";
$(data).find("table").each(function() {
html = html + "<li>" + $(this).text() + "</li>";
});
html = html + "</ul>";
$('#content').html(html);
}
);
}
</script>
</head>
<body>
<center>
<div class='connection'>
<form name='connectForm'>
Server: <input type='text' size='30' id='server' />
Username: <input type='text' id='username' />
Password: <input type='password' id='password' />
Database: <input type='text' id='database' />
<input type='button' id='connect' value='Connect' />
</form>
</div>
<div id='content'>
</div>
</center>
</body>
</html>
display.php
<?
mysql_connect($_GET['server'], $_GET['username'], $_GET['password'])
or die("Error: Could not connect to database!<br />" . mysql_error());
mysql_select_db($_GET['database']);
$content = $_GET['content'];
if ($content == "tables") {
$result = mysql_query("show tables");
$xml = "<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n";
$xml .= "<tables>";
while ($row = mysql_fetch_assoc($result)) {
$xml .= "<table>" . $row['Tables_in_blog'] . "</table>";
}
$xml .= "</tables>";
header('Content-type: text/xml');
echo $xml;
}
?>
我已经根据一些答案对代码进行了更新，但是我仍然遇到同样的问题.
I have updated the code according to a mix of a few answers, but I'm still having the same problem.
推荐答案
好，首先不要这样做，用那个"我的意思是:
Ok, firstly don't do that and by "that" I mean:
- 不要将数据库连接详细信息放在Javascript中；和
- 请勿在未清理用户输入的情况下使用它.您只是想被黑客入侵.
话虽这么说，您的主要问题似乎是$(#content)应该是$("#content").另外，在按钮上进行onclick并不是真正的jQuery方法.试试:
That being said, your main problem seems to be that $(#content) should be $("#content"). Also putting an onclick on the button isn't really the jQuery way. Try:
<body>
<div class='connection'>
<form name='connectForm'>
Server: <input type='text' id="server" size='30' name='server' />
Username: <input type='text' id="username" name='username' />
Password: <input type='password' id="password" name='password' />
Database: <input type='text' id="database" name='database' />
<input type='button' id="connect" value='Connect' />
</form>
</div>
<div id='content'></div>
<script type="text/javascript" src="/jquery-1.3.1.js"></script>
<script type="text/javascript">
$(function() {
$("#connect").click(function() {
$.get(
"display.php",
{
server: $("#server").val(),
username: $("#username").val(),
password: $("#password").val(),
database: $("#database").val(),
content: "tables"
},
function(data) {
$("#content").html("<ul></ul>");
$(data).find("table").each(function() {
$("#content ul").append("<li>" + $(this).text() + "</li>");
});
}
);
});
});
</script>
</body>
编辑:对上述内容进行了较小的更正，并对此脚本进行了测试:
minor corrections to the above and tested with this script:
<?
header('Content-Type: text/xml');
echo "<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n";
?>
<root>
<?
$tables = array('one', 'two', 'three', 'four');
foreach ($tables as $table) {
echo " <table>$table</table>\n";
}
?>
</root>
这篇关于开始jQuery帮助的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
