转换XML字符串ArrayList的 [英] Convert XML String to ArrayList

问题描述

似乎是一个基本的问题，但我找不到这个任何地方。基本上我已经有了XML链接的列表，像这样：（全部在一个字符串）

我已经有串VAR其中包含了所有的XML。只需提取HTML字符串。

 ＆LT;？XML版本=1.0编码=UTF-8＆GT？;
＆LT; fql_query_response的xmlns =htt​​p://api.facebook.com/1.0/的xmlns：XSI =htt​​p://www.w3.org/2001/XMLSchema-instance列表=真＆GT;
＆LT;照片和GT;
    <src_small>http://photos-a.ak.fbcdn.net/hphotos-ak-ash4/486603_10151153207000351_1200565882_t.jpg</src_small>
＆LT; /照片和GT;
＆LT;照片和GT;
  <src_small>http://photos-c.ak.fbcdn.net/hphotos-ak-ash3/578919_10150988289678715_1110488833_t.jpg</src_small>
＆LT; /照片和GT;
 

我想这些转换成一个ArrayList中，所以像URLArray [0]将是第一个地址为一个字符串。

谁能告诉我如何做到这一点的感谢？

解决方案

 的DocumentBuilderFactory厂= DocumentBuilderFactory.newInstance（）;
  的DocumentBuilder建设者= factory.newDocumentBuilder（）;
  InputSource的是=新的InputSource（新StringReader（的xmlString））;
  文档的DOC = builder.parse（是）;  XPathFactory是否厂= XPathFactory.newInstance（）;
  XPath的XPath的= factory.newXPath（）;
  xpath.setNamespaceContext（新PersonalNamespaceContext（））;
  XPathEx pression EXPR = xpath.compile（// src_small /文（））;  对象result = expr.evaluate（DOC，XPathConstants.NODESET）;
  节点列表节点=（节点列表）的结果;
  清单＆LT;串GT;网址=新的ArrayList＆LT;串GT;（）;
  的for（int i = 0; I＆LT; nodes.getLength（）;我++）{
      urls.add（nodes.item（ⅰ）.getNodeValue（））;
      的System.out.println（nodes.item（ⅰ）.getNodeValue（））;
  }
 

Seems like a basic question but I can't find this anywhere. Basically I've got a list of XML links like so: (all in one string)

I already have the "string" var which contains all the XML. Just extracting the HTML strings.

<?xml version="1.0" encoding="UTF-8"?>
<fql_query_response xmlns="http://api.facebook.com/1.0/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" list="true">
<photo>
    <src_small>http://photos-a.ak.fbcdn.net/hphotos-ak-ash4/486603_10151153207000351_1200565882_t.jpg</src_small>
</photo>
<photo>
  <src_small>http://photos-c.ak.fbcdn.net/hphotos-ak-ash3/578919_10150988289678715_1110488833_t.jpg</src_small>
</photo>

I want to convert these into a arrayList, so something like URLArray[0] would be the first address as a string.

Can anyone tell me how to do this thanks?

解决方案

  DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
  DocumentBuilder builder = factory.newDocumentBuilder();
  InputSource is = new InputSource( new StringReader( xmlString) );
  Document doc = builder.parse( is );

  XPathFactory factory = XPathFactory.newInstance();
  XPath xpath = factory.newXPath();
  xpath.setNamespaceContext(new PersonalNamespaceContext());
  XPathExpression expr = xpath.compile("//src_small/text()");

  Object result = expr.evaluate(doc, XPathConstants.NODESET);
  NodeList nodes = (NodeList) result;
  List<String> urls = new ArrayList<String>();
  for (int i = 0; i < nodes.getLength(); i++) {
      urls.add (nodes.item(i).getNodeValue());
      System.out.println(nodes.item(i).getNodeValue()); 
  }

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