转换到字符字符串的ArrayList? [英] Converting ArrayList Strings of to Characters?
本文介绍了转换到字符字符串的ArrayList?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
所以我得到user.I估算字符串的ArrayList也有字符的二维数组:私人的char [] []拼图;我需要帮助改变字符串的字符,所以我可以将它们输入二维数组谁能帮助??
公共类WordSearchPuzzle
{
私人的char [] []拼图;
私人的ArrayList<串GT; puzzleWords;
私人INT letterCount = 0;
私人诠释gridDimensions; 公共WordSearchPuzzle(ArrayList的<串GT; userSpecifiedWords)
{
this.puzzleWords = userSpecifiedWords; } 私人无效createPuzzleGrid()
{
INT I;
对于(i = 0; I< puzzleWords.size();我++){
letterCount = puzzleWords.size()+ letterCount;
}
gridDimensions = letterCount * 2;
拼图=新的char [gridDimensions] [gridDimensions];
}
解决方案
每个字符串更改为的 charArray 。
为(字符串项:ArrayList的){
item.toCharArray();
}
So I have an arrayList of Strings imputed by the user.I also have a 2d array of chars : private char[][] puzzle ; I need help changing the Strings to characters so I can enter them into the 2d array can anyone help??
public class WordSearchPuzzle
{
private char[][] puzzle ;
private ArrayList<String> puzzleWords ;
private int letterCount = 0 ;
private int gridDimensions;
public WordSearchPuzzle(ArrayList<String> userSpecifiedWords)
{
this.puzzleWords = userSpecifiedWords ;
}
private void createPuzzleGrid()
{
int i;
for(i = 0; i < puzzleWords.size() ; i++){
letterCount = puzzleWords.size() + letterCount ;
}
gridDimensions = letterCount * 2;
puzzle = new char[gridDimensions][gridDimensions] ;
}
解决方案
Change each string to a charArray.
for(String item : ArrayList){
item.toCharArray();
}
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