PHP从JSON获取价值 [英] PHP Get value from JSON

查看:65
本文介绍了PHP从JSON获取价值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

假设我有这个JSON:

Let's say I have this JSON:

{
  "achievement": [
    {
      "title": "Ready for Work",
      "description": "Sign up and get validated",
      "xp": 50,
      "difficulty": 1,
      "level_req": 1
    },
    {
      "title": "All Around Submitter",
      "description": "Get one piece of textual content approved in all five areas.",
      "xp": 500,
      "difficulty": 2,
      "level_req": 1
    }
}

并且我正在通过PHP进行尝试:

and I am trying this thru PHP:

$string = file_get_contents("achievements.json");
$json_a=json_decode($string,true);

$getit = $json_a->achievement['title'][1];

我正在尝试获取成就的第一个"id",即READY FOR WORK.

I'm trying to get the first "id" of the achievement.. which would be READY FOR WORK.

我该如何解决?

推荐答案

json_decode的第二个参数设置为true时,它将返回一个数组.

When you set the second parameter of json_decode to true, it will return an array.

$json_a=json_decode($string,true);

返回一个数组.

$getit = $json_a['achievement'][1]['title'];

这篇关于PHP从JSON获取价值的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆