从JSON深入获取价值 [英] Getting a value from deep inside JSON

问题描述

我正在连接到第三方API，并获取了很长的JSON字符串.我只需要一个值，但是它位于层次结构的深处.有没有一种简单的方法就可以完成整个过程?我环顾四周，但似乎没有轻松的事情.

I am connecting to a third party API and getting back a long JSON string. I only need one value from it, but it is located pretty deep inside the hierarchy. Is there a simple way to get it, without going through the whole thing? I looked all over but nothing seems easy.

这是我的示例:

"response":{"status":1,"httpStatus":200,"data":{"myDesiredInfo":"someInfo"},"errors":[],"errorMessage":null}}

我一直在尝试使用Gson，因此我可以将此Blob作为JsonObject获得.我确定有一些简单的东西，像这样:

I've been trying to use Gson so I can get this blob as a JsonObject. I was sure there's something simple, like this:

jsonObject.get("myDesiredInfo") 

或至少是这样的:

jsonObject.get("response.data.myDesiredInfo") 

但是它似乎不存在.

那么有没有可以让我做到这一点的解析器?

So is there any parser out there that will allow me to do this?

推荐答案

这是我的json字符串

This is my json string

String s="{"age":0,"name":"name","email":"emailk","address":{"housename":"villa"}}";

我使用以下代码获取房屋名称

I use following code to get housename

    JsonElement je = new JsonParser().parse(s);
    JsonObject asJsonObject = je.getAsJsonObject();
    JsonElement get = asJsonObject.get("address");
    System.out.println(s + "\n" + get);
    JsonObject asJsonObject1 = get.getAsJsonObject();
    JsonElement get1 = asJsonObject1.get("housename");
    System.out.println(get1);

以下是我的输出:

{"age":0,"name":"name","email":"emailk","address":{"housename":"villa"}}
{"housename":"villa"}
"villa"

我认为没有其他方法可以做到这一点.我还尝试了其他方式，但没有得到任何输出.

I don't think there is another way to do this. I also tried to do in other ways but i didn't get any output.

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