编组而不是编组时如何忽略JSON字段 [英] How to ignore JSON fields when marshalling not unmarshalling
问题描述
假设我在User结构中有一个密码字段.
Assume I have a password field in a User struct.
type User struct{
UserName string `json:"username"`
Password string `json:"-"`
}
我的客户通过一起发布用户名和密码来注册他们的用户.因此,如果我将JSON解码为上述结构,它将忽略密码.可以预料的但是我想知道是否只有编组时才能忽略字段.我检查了官方文档页面,但找不到任何东西.
My clients register their users by posting username and password together. So if I decode JSON to above struct, it ignores password. It's expected. But I wondered is there any way to ignore fields when only marshalling. I checked go official documentation page but couldn't find anything.
https://golang.org/pkg/encoding/json/
我可以在结构中添加一个额外的字段,但我首先需要知道是否可以使用JSON库做到这一点.
I can add an extra field into the struct but I need to know first is it possible to do that with JSON lib.
推荐答案
一种常见的方法是使用结构相同,但json
标记不同甚至结构不同的临时类型或变量:
One common approach is to use a temporary type or variable, with same structure, but different json
tags or even different structure:
type User struct {
UserName string `json:"username"`
Password string `json:"password"`
}
func (usr User) MarshalJSON() ([]byte, error) {
var tmp struct {
UserName string `json:"username"`
}
tmp.UserName = usr.UserName
return json.Marshal(&tmp)
}
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