如何在Perl中将字符串转换为json [英] How to convert string to json in perl

问题描述

我对perl还是很陌生，所以请帮助我

I am very new to perl so please help me out in following

我有一个Perl脚本来执行telnet命令.该脚本以字符串形式接收来自服务器的响应.实际上，服务器创建了一个json字符串，然后将其发送到客户端程序，但是客户端程序将其显示为string

I have one perl script to execute telnet command. This script receives response from server as string. Actually server create a json string and then it sends to client program but client program is showing it as string

问题:如何将这个字符串转换为json并从此json字符串读取数据.

Question : How I can convert this string to json and read data from this json string.

我有一个json字符串，其结构类似于以下内容

I have json string with structure similar to following

[{"success":"21","data":[{"name":"tester","lastname":"project"}]}]

---

以下是我尝试将其转换为json的最后几行

---

Following are the last lines where I have tried to convert it to json

@lines = $telnet->waitfor('/$/');
my @json;
@json = @{decode_json(@lines)};

它打印输出如下

HASH(0x1af068c)

提前感谢！！！

推荐答案

以下是用于转换JSON的代码段.修改以捕获错误.

Here is a snippet to convert the JSON. Modified to catch errors.

use strict;
use warnings;
use JSON::XS;
use Try::Tiny;
use Data::Dumper::Concise;

my $data = qq<[{"success":"21","data":[{"name":"tester","lastname":"project"}]}]>;

my $decoded;

try {
    $decoded = JSON::XS::decode_json($data);
}
catch {
    warn "Caught JSON::XS decode error: $_";
};

print Dumper $decoded;

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