如何在Bash中将字符串列表转换为JSON字符串数组? [英] How to convert string list to JSON string array in Bash?

问题描述

如何在Bash中使用包含换行符的字符串列表转换变量，像这样

How can I convert a variable in Bash with a string list containing newlines, like this

groups="group_1
group_2
group_3"

到JSON字符串数组:

to a JSON string array:

{
    [ "group_1", "group_2", "group 3" ]
}

jq有可能吗?

推荐答案

如果您的jq具有inputs，那么最简单的方法就是使用它:

If your jq has inputs then the simplest would probably be to use it:

jq -ncR '[inputs]' <<< "$groups"
["group1","group2","group3"]

否则，这是三种选择:

jq -c -n --arg groups "$groups" '$groups | split("\n")' 

echo -n "$groups" | jq -cRs 'split("\n")'

echo "$groups" | jq -R -s -c 'split("\n") | map(select(length>0))'

在任何情况下，该数组都可以轻松地合并到JSON对象中，例如通过使用| {groups: .}

In any case, the array can easily be incorporated into a JSON object, e.g. by extending the filter with | {groups: .}

如果您真的想产生无效的JSON，请考虑:

If you really want to produce invalid JSON, consider:

printf "%s" "$groups" | jq -Rrsc 'split("\n") | "{ \(.) }"'

输出:

{ ["group_1","group_2","group_3"] }

关于select(length> 0)

的说明

考虑:

Note on select(length>0)

Consider:

 jq -Rsc 'split("\n")' <<< $'a\nb'
 ["a","b",""]

包含select(length>0)的原因是为了避免在结尾加上".

The reason for including select(length>0) is to avoid the trailing "".

如果$ groups包含连续的换行符，并且保留空字符串很重要，那么您可能要使用[:-1]，例如

If $groups contains consecutive newlines, and if it is important to retain the empty strings, then you might want to use [:-1], e.g.

jq -cRs 'split("\n")[:-1]' <<< "$groups"
["group1","group2","group3"]

如果您的jq不支持[:-1]，请明确指定0:[0:-1]

If your jq does not support [:-1], make the 0 explicit: [0:-1]

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