如何在PHP中获取解码的JSON数据的值 [英] How to get values of decoded JSON data in PHP

问题描述

{"senderDetails":[{"status":"failed","senderid":"0","message":"Kindly upgrade your account to use this service."}]}

以上是我的JSON数据.我使用json_decode()函数进行解码，但是我不知道如何在PHP中分别回显每个对象的值.

Above is my JSON data. I used json_decode() function to decode, but I don't know how to echo the values of each object separately in PHP.

推荐答案

例如，如果要打印senderid:

For example, if you want to print the senderid :

<?php
$var = '{"senderDetails":[{"status":"failed","senderid":"0","message":"Kindly upgrade your account to use this service."}]}';

$decoded = json_decode($var);

var_dump($decoded);
echo($decoded->senderDetails[0]->senderid);

?>

在这种类型的计算机上使用 var_dump()很重要变量以了解如何正确访问它们.

It's important to use var_dump() on those kind of variables to understand how to access them properly.

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