无法解析来自Google的json响应 [英] unable to parse json response from google

问题描述

我正在尝试解析该网址.我已经使用了SBJsonParser，MTJSON和另一个解析器，但是在这三种情况下我都得到了NULL.

I am trying to parse Json response from This URL. I have used SBJsonParser, MTJSON and another parser but i am getting NULL in all three case.

apiUrlStr = @"http://maps.google.com/maps?output=dragdir&saddr=Delhi&daddr=Mumbai+to:hyderabad";
NSURL* apiUrl = [NSURL URLWithString:apiUrlStr];
NSString *apiResponse = [NSString stringWithContentsOfURL:apiUrl encoding:NSUTF8StringEncoding error:nil];

SBJsonParser *json = [[[SBJsonParser alloc] init] autorelease];
NSDictionary *dictionary = [json objectWithString:apiResponse];
NSLog(@"dictionary=%@", [json objectWithString:apiResponse]);

2011-12-09 16:59:01.226 MapWithRoutes [2523:207] dictionary =(null)

2011-12-09 16:59:01.226 MapWithRoutes[2523:207] dictionary=(null)

请给我一些建议

推荐答案

如果检查了您使用 JSONlint.com 所提供的网址， a>，并且JSON无效.因此任何库都无法解析.

Oke if checked the url you gave with JSONlint.com and the JSON is not valid. thus can not be parsed by any library.

如果您使用 JSONkit ，则可以为NSError对象提供parse调用以查看结果错误:

If you used JSONkit you can supply a NSError object with the parse call to see what went wrong:

NSError *error = nil;
NSDictionary *dictionary = [apiResponse objectFromJSONStringWithParseOptions:JKParseOptionNone error:&error]; 

if (!dictionary) {
   NSLog(@"Error: %@", error);
} 

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