从文件中删除给定模式之间的行(使用Unix工具) [英] Remove lines which are between given patterns from a file (using Unix tools)

问题描述

我有一个文本文件(更正确地说是德国风格" CSV文件，即用分号分隔的十进制逗号)，该文件在每行上都有一个日期和一个测量值.
在继续工作之前，我想消除一些错误的值.我想将这些剪切存储在一些脚本中，以便记录我的更正，并在必要时可以重播这些更正.

I have a text file (more correctly, a “German style“ CSV file, i.e. semicolon-separated, decimal comma) which has a date and the value of a measurement on each line.
There are stretches of faulty values which I want to remove before further work. I'd like to store these cuts in some script so that my corrections are documented and I can replay those corrections if necessary.

这些行看起来像这样:

28.01.2005 14:48:38;5,166
28.01.2005 14:50:38;2,916
28.01.2005 14:52:38;0,000
28.01.2005 14:54:38;0,000
(long stretch of values that should be removed; could also be something else beside 0)
01.02.2005 00:11:43;0,000
01.02.2005 00:13:43;1,333
01.02.2005 00:15:43;3,250

现在，我想存储诸如28.01.2005 14:52:38 + 01.02.2005 00:11:43之类的开始和结束模式的列表，脚本将剪切匹配这些开始/结束对以及它们之间的所有内容的行.

Now I'd like to store a list of begin and end patterns like 28.01.2005 14:52:38 + 01.02.2005 00:11:43, and the script would cut the lines matching these begin/end pairs and everything that's between them.

我正在考虑黑客awk脚本，但也许我想念一个已经存在的工具.

I'm thinking about hacking an awk script, but perhaps I'm missing an already existing tool.

推荐答案

看看sed:

sed '/start_pat/,/end_pat/d'

将删除start_pat和end_pat(包括)之间的行.

will delete lines between start_pat and end_pat (inclusive).

要删除多个这样的对，可以将它们与多个-e选项组合:

To delete multiple such pairs, you can combine them with multiple -e options:

sed -e '/s1/,/e1/d' -e '/s2/,/e2/d' -e '/s3/,/e3/d' ...

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