unix工具从文件中删除重复行 [英] unix tool to remove duplicate lines from a file
问题描述
我有一个工具可以生成测试并预测输出。这个想法是,如果我有一个失败,我可以将预测与实际输出进行比较,看看他们在哪里分歧。问题是实际输出包含一些行两次,这会混淆 diff
。我想删除重复的,所以我可以很容易地比较。基本上,像 sort -u
,但没有排序。
I have a tool that generates tests and predicts the output. The idea is that if I have a failure I can compare the prediction to the actual output and see where they diverged. The problem is the actual output contains some lines twice, which confuses diff
. I want to remove the duplicates, so that I can compare them easily. Basically, something like sort -u
but without the sorting.
有任何unix命令行工具, ?
Is there any unix commandline tool that can do this?
推荐答案
概要
uniq [OPTION] ... [INPUT [OUTPUT]]
uniq [OPTION]... [INPUT [OUTPUT]]
DESCRIPTION
DESCRIPTION
丢弃来自INPUT(或标准输入)的连续相同行中的所有行,写入OUTPUT(或标准输出)。
Discard all but one of successive identical lines from INPUT (or standard input), writing to OUTPUT (or standard output).
或者,如果你想删除不相邻的重复行,这个perl片段将会这样做:
Or, if you want to remove non-adjacent duplicate lines as well, this fragment of perl will do it:
while(<>) {
print $_ if (!$seen{$_});
$seen{$_}=1;
}
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