使用LINQ扁平化XML文件的简单方法 [英] Easy way to flatten XML file with LINQ

问题描述

LINQ是否有一种简单的方法来展平XML文件?

Is there an easy way with LINQ to flatten an XML file?

我可以用XSLT看到很多方法，但是想知道LINQ的最佳选择是什么?

I can see a number of ways with XSLT but wondered what the best option with LINQ would be?

我不能完全按照stackoverflow似乎过滤人字形字符的方式来放置xml结构.但是它是这样的

I cant put the xml structure up exactly as stackoverflow seems to filter chevron chars. But its something like this

nodeA

-nodeA1

-nodeA2

NodeB

我想结束

nodeA

nodeA1

nodeA2

NodeB

推荐答案

确定；它取决于您想要的输出-使用XElement，您需要做一些工作以删除所有后代节点等.但是，使用XmlDocument实际上非常简单:

OK; it depends on the output you want - with XElement you'd need to do a bit of work to remove all the descendent nodes etc. However, it is actually quite simple with XmlDocument:

string xml = @"<xml><nodeA><nodeA1/><nodeA2/></nodeA><NodeB/></xml>";

XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);

XmlDocument clone = new XmlDocument();
XmlElement root = (XmlElement) clone.AppendChild(clone.CreateElement("xml"));
foreach(XmlElement el in doc.SelectNodes("//*")) {
    root.AppendChild(clone.ImportNode(el, false));
}
Console.WriteLine(clone.OuterXml);

输出:

<xml><xml /><nodeA /><nodeA1 /><nodeA2 /><NodeB /></xml>

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[是] 在这种情况下要定义展平"吗?即之前"和之后"? XDocument具有Descendants()和DescendantNodes()可以完成此任务...

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[was] Care to define "flatten" in this context? i.e. "before" and "after"? XDocument has Descendants() and DescendantNodes() which might do the job...

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