如何在Linux中生成带有绝对路径的文件列表? [英] How can I generate a list of files with their absolute path in Linux?

问题描述

我正在编写一个将文件路径作为输入的Shell脚本.

由于这个原因，我需要生成具有完整路径的递归文件列表.例如，文件bar具有路径:

/home/ken/foo/bar

但是，据我所知，ls和find都只给出相对路径清单:

./foo/bar   (from the folder ken)

这似乎是一个显而易见的要求，但是我在find或ls手册页中看不到任何内容.

如何在Shell中生成文件列表及其绝对路径?

解决方案

如果为find提供绝对路径，它将打印绝对路径.例如，要查找当前目录中的所有.htaccess文件:

find "$(pwd)" -name .htaccess

，或者如果您的外壳将$PWD扩展到当前目录:

find "$PWD" -name .htaccess

find只是将给定的路径添加到从该路径到文件的相对路径.

Greg Hewgill 还建议使用pwd -P来解析当前目录中的符号链接.

I am writing a shell script that takes file paths as input.

For this reason, I need to generate recursive file listings with full paths. For example, the file bar has the path:

/home/ken/foo/bar

but, as far as I can see, both ls and find only give relative path listings:

./foo/bar   (from the folder ken)

It seems like an obvious requirement, but I can't see anything in the find or ls man pages.

How can I generate a list of files in the shell including their absolute paths?

解决方案

If you give find an absolute path to start with, it will print absolute paths. For instance, to find all .htaccess files in the current directory:

find "$(pwd)" -name .htaccess

or if your shell expands $PWD to the current directory:

find "$PWD" -name .htaccess

find simply prepends the path it was given to a relative path to the file from that path.

Greg Hewgill also suggested using pwd -P if you want to resolve symlinks in your current directory.

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