如何在 Linux 中生成带有绝对路径的文件列表? [英] How can I generate a list of files with their absolute path in Linux?

问题描述

我正在编写一个将文件路径作为输入的 shell 脚本.

I am writing a shell script that takes file paths as input.

出于这个原因，我需要生成具有完整路径的递归文件列表.例如，文件 bar 的路径是:

For this reason, I need to generate recursive file listings with full paths. For example, the file bar has the path:

/home/ken/foo/bar

但是，据我所知，ls 和 find 都只给出相对路径列表:

but, as far as I can see, both ls and find only give relative path listings:

./foo/bar   (from the folder ken)

这似乎是一个明显的要求，但我在 find 或 ls 手册页中看不到任何内容.

It seems like an obvious requirement, but I can't see anything in the find or ls man pages.

如何在 shell 中生成文件列表，包括它们的绝对路径?

How can I generate a list of files in the shell including their absolute paths?

推荐答案

如果你给 find 一个绝对路径开始，它会打印绝对路径.例如，要查找当前目录中的所有 .htaccess 文件:

If you give find an absolute path to start with, it will print absolute paths. For instance, to find all .htaccess files in the current directory:

find "$(pwd)" -name .htaccess

或者如果你的 shell 将 $PWD 扩展到当前目录:

or if your shell expands $PWD to the current directory:

find "$PWD" -name .htaccess

find 简单地将它提供的路径添加到从该路径到文件的相对路径.

find simply prepends the path it was given to a relative path to the file from that path.

Greg Hewgill 还建议使用 pwd -P 如果您想解析符号链接在您当前的目录中.

Greg Hewgill also suggested using pwd -P if you want to resolve symlinks in your current directory.

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