在python中的列表中查找序列的索引 [英] Find indexes of sequence in list in python

问题描述

我很新，我希望它不太明显，但是我似乎无法为以下问题找到一个简短而准确的答案.

I am quite new and I hope it's not too obvious, but I just can't seem to find a short and precise answer to the following problem.

我有两个列表:

a = [2,3,5,2,5,6,7,2]
b = [2,5,6]

我想查找第二个列表(b)的所有索引何时在第一个列表(a)中，以便得到如下内容:

I would like to find when all the indexes of the second list (b) are in the first list (a), so that I get something like this:

索引:3, 4, 5或b = a[3:6]

推荐答案

具有列表理解功能:

>>> [(i, i+len(b)) for i in range(len(a)) if a[i:i+len(b)] == b]
[(3, 6)]

或带有for循环:

>>> indexes = []
>>> for i in range(len(a)):
...    if a[i:i+len(b)] == b:
...        indexes.append((i, i+len(b)))
... 
>>> indexes
[(3, 6)]

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