Python：在浮点列表中查找最小项的索引 [英] Python: Find index of minimum item in list of floats

问题描述

如何在Python列表中找到最小项目的索引？如果他们是整数，我会简单地做：

$ $ $ p $ minIndex = myList.index（min（myList））

但是，浮动列表出现以下错误，我认为是因为浮动等值比较比较麻烦。

  ValueError：0.13417985135不在列表中
  

现在，我知道我可以简单地滚动列表并比较每个项目，看它是否是< （min + 0.0000000000001）和>（min - 0.0000000000001），但这有点凌乱。有一个更优雅的（最好是内置的）的方式来找到浮动列表中最小的项目的索引？

解决方案

你有效地扫描列表一次找到最小值，然后再次扫描找到索引，你可以一次完成：

 来自操作员导入itemgetter 
 min（枚举（a），key = itemgetter（1））[0] 
  

How can I find the index of the minimum item in a Python list of floats? If they were integers, I would simply do:

minIndex = myList.index(min(myList))

However, with a list of floats I get the following error, I assume because float equality comparison is rather iffy.

ValueError: 0.13417985135 is not in list

Now, I know that I could simply scroll through the list and compare each item to see whether it is < (min + 0.0000000000001) and > (min - 0.0000000000001), but that is kinda messy. Is there a more elegant (preferably built-in) way to find the index of the smallest item in a list of floats?

解决方案

You're effectively scanning the list once to find the min value, then scanning it again to find the index, you can do both in one go:

from operator import itemgetter
min(enumerate(a), key=itemgetter(1))[0] 

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